I need to know how to solve the following equation using the quadratic formula and I do not understand the quadratic formula at all.
-z+2z-7=0
This isn't a quadratic equation, it's a linear one. You need a z2 term somewhere to make it quadratic.
-z+2z-7=0
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OK......first, let's multiply both sides by (-1) just to make everything look "nicer" we have
1z - 2z + 7 = 0
The quadratic formula is given by
And, in our equation b = -2 a = 1 and c = 7
So we have
x = (-(-2) ± SQRT[(-2)2 - (4)(1)(7)] ) / [2(1)] =
[ 2 ± SQRT [4 -(28)] ]/ 2 =
[ 2 ± SQRT ( -24 ) ] / 2
Since the SQRT (-24) is not a real number, we don't have any real solutions..........
Here's a website that also might help you......
http://www.mathsisfun.com/algebra/quadratic-equation.html