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I need to know how to solve the following equation using the quadratic formula and I do not understand the quadratic formula at all.

-z+2z-7=0

 Apr 24, 2014

Best Answer 

 #3
avatar+118587 
+5

-z+2z-7=0

ALAN IS CORRECT.  

YOU CANNOT USE THE QUADRATIC FORMULA BECAUSE IT IS NOT A QUADRATIC EQUATION.

Perhaps you actually meant

-z2+2z-7=0  but that has no solutions so maybe you meant something else ?????

 Apr 25, 2014
 #1
avatar+33603 
+5

This isn't a quadratic equation, it's a linear one. You need a z2 term somewhere to make it quadratic.

 Apr 24, 2014
 #2
avatar+128079 
0

-z+2z-7=0

----------------------------------------------------------------------------------------------------------------------------

OK......first, let's  multiply both sides by (-1) just to make everything look "nicer"   we have

1z - 2z + 7 = 0

The quadratic formula is given by

x = [-b+/-sqrt(b^2-4ac)]/2a

And, in our equation b = -2  a = 1 and c = 7

So we have

x = (-(-2) ± SQRT[(-2)2 - (4)(1)(7)] ) / [2(1)]  = 

[ 2 ± SQRT [4 -(28)] ]/ 2 =

[ 2 ± SQRT ( -24 ) ] / 2

Since the SQRT (-24) is not a real number, we don't have any real solutions..........

Here's a website that also might help you......

http://www.mathsisfun.com/algebra/quadratic-equation.html

 Apr 24, 2014
 #3
avatar+118587 
+5
Best Answer

-z+2z-7=0

ALAN IS CORRECT.  

YOU CANNOT USE THE QUADRATIC FORMULA BECAUSE IT IS NOT A QUADRATIC EQUATION.

Perhaps you actually meant

-z2+2z-7=0  but that has no solutions so maybe you meant something else ?????

Melody Apr 25, 2014

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