The tangent to the circumcircle of triangle WXY at X is drawn, and the line through W that is parallel to this tangent intersects XY at Z If XY=14 and WX=6 find YZ.
+9519 Let P be the point on the tangent at the bottom of the image.
Note that \(\angle PXZ = \angle XZW\) since they are alternate angles of the pair of parallel lines.
Also, \(\angle PXZ = \angle XWY\) since they are angles in alternate segments.
Therefore \(\angle XZW = \angle XWY\). Also, \(\angle ZXW = \angle WXY\) since they are the same angle.
By AA postulate, \(\triangle XZW \sim \triangle XWY\).
Let YZ = t. Then by similar triangles, \(\dfrac{XZ}{XW} = \dfrac{XW}{XY}\). i.e., \(\dfrac{14 - t}{6} = \dfrac{6}{14}\).
Can you take it from here?
