help pls

Combining the areas of all the regions, I'm getting that the area of the large square is 3 + 2*sqrt(3).

The height, H,  of one of the equilateral triangles   can be found as

tan 60   =   H /(1/2)

√3/2  = H

The diagonal of the square  =   2H  + 1 =   √3  +  1

The side of the larger  square = diagonal / √2  =     [ √3 + 1  ]  / √2

So....the area  of the larger square  =  

[ √3 + 1 ] ^2 / 2     =    [ 3 + 2√3 + 1' / 2   =  [4 + 2√3 ] / 2   =   [ 2 + √3 ]  units^2  ≈  3.732 units^2 

Smaller square side                  a = 1

Equilateral triangle side             s = 1

Equilateral triangle height         h =  sqrt [ s² - ( s/2)² ]       h = sqrt [ 1 - (1/2)² ]  = 0.866

The area of a larger square      A = 2( h + a/2 )²                 A = 2(0.866+0.5)²  =  3.732 u²