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Mike, Nathan and Owen each had some marbles and decided to play a game

with their marbles.

 

In round 1, MIke lost \({1\over 2}{}{}\)of his marbles to Nathan.

 

In round 2, Nathan lost \({1\over 2}{}{}\)of his total number of marbles to Owen.

 

In round 3, Owen lost \( {1\over 2}{}{}\)of his total number of marbles to Mike.

 

In the end, Mike, Nathan and Owen ad 124, 88 and 68 marbles respectively.

How many marbles did Nathan have at first?

 Sep 15, 2021
 #1
avatar+23 
+4

Nathan marbles in the beginning=120


Before round 3

Owen= 68x2=136

Mike=124-(136/2)=56

 

Before round 2

Nathan=88x2=176

Owen=136-88=48

 

Before round 1

Mike=56x2=112

nathan=176-56=120

 Sep 15, 2021
 #2
avatar+53 
+1

Thx

 

 

 

 

.

Sturasion12345  Sep 15, 2021

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