The sum of seven consecutive positive integers is 77. The largest of these integers is what?
+934 The seven consecutive integers can be written as:
\(x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)\)= \(7x+21\)= \(77\)
\(7x+21=77\)
\(7x=56\)
\(x=8\)
Since x is the smallest integer and (x+6) is the largest answer, 8+6 = 14 which is the largest number.
