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If h(y)=(1+y)/(2-y), then what is the value of h-1(5)? Express your answer in simplest form.

 May 17, 2022
 #1
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0

\(h^{-1}(5) = 2/3\)

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 May 17, 2022
 #2
avatar+11 
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Thank you!

 May 18, 2022
 #3
avatar+11 
0

The answer was -6.

 May 18, 2022
 #4
avatar+9466 
+1

Substitute h(y) = 5, and see what the value of y is. That value is h^(-1) (5).

 

\(5 = \dfrac{1 + y}{2 - y}\\ 10 - 5y = 1 + y\\ 6y = 9\\ y = \dfrac32\)

 

Therefore \(h^{-1}(5) = \dfrac32\).

 May 18, 2022

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