If h(y)=(1+y)/(2-y), then what is the value of h-1(5)? Express your answer in simplest form.
\(h^{-1}(5) = 2/3\)
Thank you!
The answer was -6.
Substitute h(y) = 5, and see what the value of y is. That value is h^(-1) (5).
\(5 = \dfrac{1 + y}{2 - y}\\ 10 - 5y = 1 + y\\ 6y = 9\\ y = \dfrac32\)
Therefore \(h^{-1}(5) = \dfrac32\).