really need help!

Center rectangle   (x+2    + x-1)  *   (x-1)  = (2x+1)(x-1) = 2x^2 -x-1

     plus TWO squares    2 *  ( x-1)(x-1)   = 2 (x^2-2x+1)

Add the reds for area  

we have 2(x-1)^2+(x-1)((x-1)+(x+2)) we can distribute to get 2x^2+−4x+2+x^2+−x+x^2+2x+−x+1+−x+−2 and then combine like terms to get (2x^2+x^2+x^2)+(−4x+−x+2x+−x+−x)+(2+1+−2) which can be simplfied as 4x^2+−5x+1 then becomes (D)4x^2−5x+1 so we have that the area is \(\boxed{(D)4x^2−5x+1}\)