l 3x + 2 l = 2
We have two equations here
3x + 2 = 2 3x + 2 = - 2
Subtract 2 from both sides
3x = 0 3x = - 4
Divide both sides by 3
x = 0 x = -4/3
f(x) = x^2 -2x + 2
The domain is all real numbers
To find the range we need to plug -b/ [2a] into the function where b = -2 and a = 1
So.... -b/ [2a] = 2 / [2 * 1 ] = 2/2 = 1 ,.....and this is the x coordinate of the vertex
So....the y coordinate of the vertex is
f(1) = (1)^2 - 2(1) + 2 = 1
This parabola points upward so the vertex is (1,1)
And y = 1 is the low point on the function
So.....the range is [1, infinity )
The first answer is correct