Membres: admin

16 Questions
1410 Answers

2316

+3146

Neue Datenschutzrichtlinie, Mai 2018

Hallo,

Diese Webseite wurde aktualisiert mit kleineren Anpassungen an die DS-GVO.
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Hors sujet

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admin 27 mai 2018

+19

3479

+3146

New Privacy Policy, May 2018

Hello,

this website was updated today because of some legal changes here in Europe. ("GDPR").
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Hors sujet

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admin 27 mai 2018

2271

+3146

New version is online for two weeks now, any problems?

Hi,

Any problems? You can use the "Report a Problem" link in the footer, or send me an email to britnex+bugs@gmail.com
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admin 12 sept. 2015

+20

2716

+3146

New website is online.

Hi,

Any problems? You can use the "Report a Problem" link in the footer, or send me an email to britnex+bugs@gmail.com , thank you!
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Melody ●●●●●●●●●●●●●●●●

admin 30 août 2015

2574

+3146

Neue Version der Webseite ist online

Hi,

Probleme bitte per Email an britnex+bugs@gmail.com melden, Danke!
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admin 30 août 2015

+67

4475

+3146

three times ten to the power of negative 2

help what is 3x10to the power of negative 2

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admin 26 janv. 2012

+3146

MA
MT
MH
AM
AT
AH
TM
TA
TH
HM
HA
HT

first time you can choose 4
second time you can choose 3

total: 4*3=12 but, there are 2 (=2!) ways two letters can be arranged, so you have to divide by that. so (3*4)/2= 6

"from n choose r":
[input]ncr(4,2)[/input]

admin29 mai 2013

+3146

hi!

Lamehe:
Now let's just wait for someone to point out a really stupid mistake I made..

not really a mistake, the reason behind these different results is the interpretation of "-v²". this could be "-(v²)" or "(-v)²", same as the result for "-2^2" could be 4 or -4. web2.0calc interprets your input "-v²" as "(-v)²". I you want the other interpretation you can use parenthesis:

[input]-v²+6v-1/2=0[/input]
[input]-(v²)+6v-1/2=0[/input]

admin25 mai 2013

+3146

dontknow:
hello, how do I solve this?

1/x - x/5 = 0

[input]1/x - x/5 = 0[/input]

1/x - x/5 = 0 |+x/5
1/x = x/5 | *x
1 = x^2/5 |*5
5 = x^2
x^2 = 5 | sqrt
x= +sqrt(5) and -sqrt(5)

admin23 mai 2013

+3146

[input]8-(x+5)=2[/input]

8-(x+5)=2
8-x-5=2
8-x-5+5=2+5
8-x=7
8-x+x=7+x
8=7+x
8-7=7-7+x
1=x
x=1

admin21 mai 2013

+3146

function syntax of pi(1):
[input]2pi(1)^2[/input]

[input]2pi*(1)^2[/input]

[input]2pi*1^2[/input]

admin16 mai 2013

+3146

sin^-1(0.5)
[input]sin^-1(0.5)[/input]

asin(0.5)
[input]asin(0.5)[/input]

admin12 mai 2013

+3146

[input]4*e^x=52[/input]

4*e^x=52
4*e^x/4=52/4
e^x=52/4
e^x=13

assume x>0:
ln(e^x)=ln(13)
x=ln(13)

admin8 mai 2013

+3146

(sin(x)-cos(x))(sin(x)+cos(x))
expand:
sin(x)^2-cos(x)*sin(x)+sin(x)*cos(x)-cos(x)^2
with: cos(x)^2+sin(x)^2=1 is: sin(x)^2=1-cos(x)^2
(1-cos(x)^2)-cos(x)*sin(x)+sin(x)*cos(x)-cos(x)^2
with: -cos(x)*sin(x)+sin(x)*cos(x) = 0
(1-cos(x)^2)-0-cos(x)^2
1-cos(x)^2-cos(x)^2
1-2*cos(x)^2

with: cos(x)^2+sin(x)^2=1
cos(x)^2+sin(x)^2-2*cos(x)^2
1*cos(x)^2+sin(x)^2-2*cos(x)^2
1*cos(x)^2-2*cos(x)^2+sin(x)^2
-cos(x)^2+sin(x)^2
with: cos(2x)=cos(x)^2-sin(x)^2 is: -cos(2x)=-cos(x)^2+sin(x)^2
-cos(x)^2+sin(x)^2
-cos(2x)

admin7 mai 2013

+3146

ronny:
Er bekommt soviel silberbarren wie er mit samt seiner Rüstung wiegt.

silberbarren = prinz + ruestung

ronny:
Er bekommt 100 silberbarren

silberbarren=100

ronny:
Der Prinz wiegt 60 silberbarren mehr als seine Rüstung.

prinz = ruestung+60

Also 3 Gleichungen:
silberbarren = prinz + ruestung
silberbarren=100
prinz = ruestung+60

einsetzen:
100=prinz + ruestung
prinz = ruestung+60

einsetzen:
100=(ruestung+60) + ruestung
100=ruestung+60+ruestung
100-60=ruestung+ruestung
100-60=2*ruestung
40=2*ruestung
40/2=ruestung
ruestung=20

ronny:
Was wiegt seine Rüstung ?

Gewichtsequivalent zu 20 Silberbarren.

[input]solve( silberbarren = prinz + ruestung, silberbarren=100, prinz = ruestung+60)[/input]

admin29 avr. 2013

+3146

[input]log( 27, 3)[/input]
[input]log( 4^5 , 4)[/input]

admin25 avr. 2013

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