We have the equation: \(\large{{{x +2} \over x} \times {x+3 \over x+1} \times {x+4 \over x+2} = 10}\)
Because there is the term \(x+2\) in both the numerator and the denominator, we can cancel them out.
This gives us: \(\large{{x+3 \over x+1} \times {x+4 \over x} = 10 }\)
Simplifying the left-hand side gives us: \(\large{{{x^2 + 7x + 12} \over {x^2 + x}} = 10 }\).
From the equation, we know that the numerator (\(x^2 + 7x + 12 \)) must be 10 times the denominator (\(x^2 + x \))
Thus, we have: \(10(x^2 +x) = x^2 + 7x + 12 \)
Now, we have to solve the equation, and subsitute our values into the first fraction (\(\large{x+2 \over x}\))
Can you take it from here?