I think you are wrong because when 2i^2=-2
(3+2i)/(1-i)
= ((3+2i)*(1+i))/((1-i)*(1+i))
= (3+3i+2i+2i^2)/(1+i-i-i^2)
= (3+(-2)+5i)/2
= (1+5i)/2
(1+5i)/2 or 1/2+5/2i
1/(1*4)+1/(4*7)+1/(7*10)
= 1/4+1/28+1/70
Using the common denominator of 140:
35/140+5/140+2/140
= 42/140
= 3/10
3/10 or 0.3
The answer was \(\frac32\)
