More detailed explanations:https://www.mathwarehouse.com/riddles/math-riddles.php
\((f\times g)(x)=f(x)\times g(x)\)
\((x^2-3x+2)(x^3-8)=x^6-8x^2-4x^4+24x+2x^3-16=x^6-4x^4+2x^3-8x^2+24x-16\)
You are very welcome!
:P
y=mx+b
m=3
y=3x+b
x=1, y=7
7=3(1)+b
7=3+b
b=4
Equation: y=3x+4
Same here PM!
I believe Rom is correct
a. The graph is positive when it is above the y-axis; if you can see, it is positive from (-6, -4) and (3, 13).
b. So? Can you find the negative using this method?
\((x^a)^b\)=\(x^{ab}\)
\((y^3)^2=y^{3\times 2}=y^6\)
Hmm... not sure...
If a function is positive the y-value is greater than 0; it's above the y-axis.
Can you retry? (one of the answer choices you said are right.)
Ok...