CPhill

√ [ 7x ] ( √x  - 7√7 )  =

(We are just using the distributive property here, like normal )

√ [7x] * √x    -    √ [7x] *  7√ 7  =

√ [ 7 * x^2 ]   -   7√ [  7x * 7 ]  =

x√ 7  -  7 √  [49 x ]   =

x √7  -  7 * 7√ x  =

x√7  -  49√x

Correct, RP  !!!!!

Mmmmm.....these aren't showing up for me.....

Nothing shows up for me, NSS !!!

OK  !!!!

Can't use the tangent here

We know the side adjacent to the 28° angle  and we are trying to find the side opposite the right angle (the hypotenuse )

And the trig function that relates the adjacent  side and the hypotenuse is the cosine

cos (angle measure )  =  adjacent / hypotenuse

oos ( 28° )  =  11 / x      multiply both sides by x

x cos (28°)  = 11      divide both sides by cos (28°)

x   =  11 / cos (28° )  =  12.46

HAHAHA!!!...I didn't actually answer it....I just confirmed your correct answer.....  

Correct  !!!!

The angle bisector of  ACB  sets up the following ratio :

AD / BD  =  AC / BC

So we have that

x / 4.2  = 5 / 6       multiply both sides by 4.2

x  =  4.2 * 5  / 6     =   3.5

You're on the right track...!!!