gwenspooner85

In Latex on this site you could also do 0. \overline{repeating numbers in the decimal}

There was a guest who kept cussing at me too, I think it's probably the same one.

Amanda's portion is 1/10 of the total, which is $20. Then the total amount is $200. 

b-13 and b must add up to b+33. We form an equation:

(b-13)+b=b+33

2b-13=b+33

b=46

We break the inequality down into two inequalities: \(\frac{1}{3}t-5 . We solve for  \(\frac{1}{3}t-5  first.

\(\frac{1}{3}t-5 -\frac{9}{2}\)

Then we solve for \(t-2\le-3t+7\).

\(t-2\le-3t+7\\ = 4t\le9\\ = t\le\frac{9}{4}\)

Then t must be \(-\frac{9}{2} . In interval notation this is  \(\boxed{(-\frac{9}{2}, \frac{9}{4}]}\).

b-36 and b-33 must add up to b so we have:

(b-36)+(b-33)=b

2b-69=b

b=69

We know each hour space is 360/12= 30 degrees. When it is 9:20, the hour hand is 1/3 the way between 9 and 10. It is 10 degrees above 9 o clock. Between the hours 4 and 9 is 5 spaces so 5*30=150. The smaller angle in the clock is 150+10=160 degrees. Then the bigger angle is 360-160=200 degrees.

Notice that x-2 and x+1 are factors of x^2-x-2.

\(\frac{x+7}{x^2-x-2}=\frac{a}{x-2}+\frac{b}{x+1}\\ \frac{x+7}{x^2-x-2}=\frac{a(x+1)}{x^2-x-2}+\frac{b(x-2)}{x^2-x-2}\\ x-7=a(x+1)+b(x-2)\\ x-7=ax+a+bx-2b\\\)

ax+bx must add up to the x term on the left side, which is x. a-2b must subtract to the constant on the left side, -7. We then have a system of equations.

a+b=1

a-2b=-7

We find that a= -5/3 and b=8/3.

We have 1/2 x 1/100 x 40.

1/2 x 1/100 x 40

= 1/200 x 40

= 40/200

= 1/5

1/5 is less than a number which is 1/5+1=6/5=1.2.

Let x be Paulo's current age and x+18 Sandra's. We form an equation of their ages in 13 years.

(x+18)+13=2(x+13)

x+31=2x+26

x=5

Sandra is x+18 so her age is 23 years old.

What the heck is wrong with you? Why must you use such explicit words instead of saying something normally?! So what if I got it wrong?