hipie

a(x+u)(x+u) + v

a(x^2 + 2ux + u^2) + v

ax^2 + 2aux + au^2 + v = 4x^2 + 15x + 2

a, u, v are real numbers.

now we know a = 4, then substitute in. 

I think you can take it from here.

Use the formula a_n = a_1 r^n-1

a_n = (16 * 9^n-2)/(4^n-1) (common ratio) 

a_8=(16*9^6)/(4^7)

a_8 = ?

a+b+c=47.

if we simplify and combine like terms, we will get 5x^2 - 30x + 90. 

it will then = 5(x^2 - 6x)+90

if we simplify the parenthesis, it will be 5[(x-3)^2 - 9] + 90. notice how I added the - 9 because -3 * -3 = 9.

Then, I'll multiply and distrubute the 5 to the -9, which is -45

If we combine like terms, the final will be 5(x-3)^2 + 45. 5-3+45=47.

Would you care to look at that again guest.?

Solve the rational expression and combining terms gives you, t=5, 2

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Are you trying to evaluate x? If yes, then 4x+12=7x+3, 9=3x, divide both sides by 3, and x = 3

t=/ 0. (-inf, 0)U(0, Inf) This is because if zero was substituted in, then 1-1 = 0 and 0 cannot be in the Denominator.

8+4=12, so the expression = 12 if x=2

wait is it (3)/(5x^3)-9?