Thanks for the A2A.
First, let's convert .92 into a fraction.
That would be 92/100. Now let's figure out the probability of 1 case of 1 number(there are 2 numbers, 8 and 9).
To have exactly 8 students, that would be \(\frac{92^8*8}{{100}^{9}}\) probability for 1 case. Compute that and you'll get .041.
To find the total number of cases in #8, we can use the combination formula to get \(\frac{9!}{8!}\) which is simplified to 9.
.041 multiplied by 9 is approximately .37.
Now we can figure out the probability for exactly 9 students.
It is .472. There is only one way we can sort 9 students from 9, so we keep it.
.37+.472 is approximately 84.17%.
Cheers!