\(29
if that equation no have real roots, then discriminant must be < 0.
\(6^2-4\times(-1)\times(20-b)<0\)
\(36+80-4b=29-b<0\)
because that line are parallel, then :
111 + b = 180 => b = 69.
a + 39 = 180 => a = 141.
So, the answer is trapezoid; a = 141, b = 69
Diagonal :
\(D=\sqrt{(4(7))^2+(3(7))^2}=\sqrt{784+441}=\sqrt{1225}=35\)
Thanks! Thats correct
2 2 1 is 15 ways not 10.
Total 41
\((2x+3)^2-(2x+5)(2x-5)=34\)
\((4x^2+12x+9)-(4x^2-25)=34\)
\(12x+34=34\)
\(12x=0\)
\(x=0\)
3x - 8y = 29
3x + y = -2
____________ -
-9y = 31
y = -31/9
3x + (-31/9) = -2
3x = 13/9
x = 13/27
\((x+8)+(2x-3)+(6x-5)=180\)
\(9x=180\)
\(x=20\)
\(\angle J=x+8=20+8=28\)
\(\angle K=6x-5=120-5-115\)
\(\angle L=2x-3=40-3=37\)
Diagram B, because x+2.6=10.4
