jimkey17

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We can use algebra s=speed and l=length (500+l)/s=20, (1900-l)/s=30 we have that s=48 and l=460 by Adding the equations in order to solve for the first variable. Then we plug this value into the other equations in order to solve for the remaining variables. 

so we have the \(\text{speed}=48,\text{ and }\boxed{\text{length of the train}=460m}\)

we do 5.70*25.5=145.35(total price) and we can use algebra x+y=25.5(weight) and (2.20)x+(7.30)y=145.35 we have x+y=25.5 and we subtract y from both sides to get x=25.5-y then we substitute x with 25.5-y in (2.2)x+(7.3)y=145.35 which becomes 2.2(−y+25.5)+(7.3)y=145.35. We simplify both sides of the equation to get 5.1y+56.1=145.35 and subtract 56.1 to get 5.1y=89.25 so we get that y=17.5 and x=22.5-17.5=8 

and we have \(\boxed{x=8}\text{ and } \boxed{y=17.5}\)

Um a fraction is a numerical quantity that is not a whole number 

EXAMPLE: 1/3,5/7, 4 5/7, 86/21

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten

 With a dot in beetween a whole number and the decimal part

Example:  0.0538483

We have 3/4*5/9=(3*5)/(4*9)=15/36 so we have \(\dfrac{15}{36}\)

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That's exactly what i said

After the And we get I mean And we get 13

We know that 96889010407 is 7^13 so \(log_7(96889010407)=13 \)and we get 

cos(300)=1/2 or \(\cos(300)=\dfrac12\)

we have 2(x-1)^2+(x-1)((x-1)+(x+2)) we can distribute to get 2x^2+−4x+2+x^2+−x+x^2+2x+−x+1+−x+−2 and then combine like terms to get (2x^2+x^2+x^2)+(−4x+−x+2x+−x+−x)+(2+1+−2) which can be simplfied as 4x^2+−5x+1 then becomes (D)4x^2−5x+1 so we have that the area is \(\boxed{(D)4x^2−5x+1}\)

we know that it has the same ration as 63:57 so we have 57/63*21=1197/63=19 so we have that the length of CG is \(\boxed{19}\)

we seperate them into a rectangle and a triangle where the rectangle's area is 9*20=180 and the triangle's area is (14-9)*(20-11)/2=5*9/2=45/2=22.5 so the area of the shape is 180+22.5=202.5 so we get that the area of the shape is \(\boxed{202.5}\)