MaxWong

If y = log x,

Then x = 10^y .

$3^{2x}-9(3^{-2x})=8\\ 3^{4x} - 9 = 8(3^{2x})\\ 3^{4x} - 8(3^{2x}) - 9=0\\ \text{Let u = }3^{2x}\\ u^2 - 8u - 9 = 0\\ (u+1)(u-9) = 0\\ u = -1 \text{ OR }u=9\\ 3^{2x} = -1\text{(rejected) OR }3^{2x} = 9\\ 3^{2x} = 9\\ x = 1$

input = 3^(1-1)

OR you want 3^(2-1)

cos(78) = 0.207911690818

Btw, cosine, not cosign.

2919.219/134 = 21.7852164179104478.

:)

$\left(\dfrac{-1}{2}\right)^2\\ =\dfrac{(-1)^2}{2^2}\\ =\dfrac{1}{4}$

$7\times2^{3x-5} = 53\\ 2^{3x-5}=\dfrac{53}{7}\\ \log_2 (2^{3x-5})=\log_2\dfrac{53}{7}\\ 3x - 5 = \log_2\dfrac{53}{7}\\ x = \dfrac{\log_2\dfrac{53}{7}+5}{3}$

Which is 7.920565532505595

$\boxed{\color{aqua}\log{\sqrt x}=\dfrac{\log x}{2}}$

Btw the extension is just repeating the first 2 columns of the matrix.

Btw the extension is just repeating the first 2 columns of the matrix.