MaxWong

Inequality is a kind of equation, but where the equal sign is replaced by <, >, \(\geqslant\), and \(\leqslant\). 

Wot!?

So those are guests??

I thought that was an error!!

I know that!! But I am so careless......

If we substitute x = 3 into the original equation, we get sqrt(64) = 3 - 11 = -8. Since sqrt(64) = 8 not -8, so I should reject the solution x=3.

You do \(x+(1+10\%)x+(1+10\%)^2x+(1+10\%)^3x\)

which is 4.641x

Well..... I am not a very careful person and I made a mistake.....

Thank you admins and moderators: The problem has been solved.

~Max.

Wait I found a mistake

x + 2x = 72/2 lol

how could i get that wrong

Did you eat the data?

Is the data very delicious?

Yum Yum :)

~The smartest cookie in the world.

All primes except 2 is an odd number(Think about it. Why?). When p > 2, it must be an odd number.

Sum of the squares of 2 odd numbers is an even number. Therefore sum of the squares of 2, and 2 prime numbers is also an even number, not a prime number.

I tested a few combinations which involves p = 5 and I don't know why the results are always divisible by 3.

Tested a few combinations which involves p = 7 and I don't know why the results still are always divisible by 3.

I assume that all combinations involving p \(\geq\) 5 will always divisible by 3.

Therefore only 1 value is possible for p.
 

Why on Earth is everything divisble by 3? lol