(a) I would choose to eliminate x from the equation. (Actually it is your choice to eliminate which variable)
(b) I chose equation 2 and equation 3 because this makes life easier :P.
x+3y+2z=5−−−−−(2)4x+4y+3z=13−−−−(3)From equation 2: 4x+12y+8z=20−−−−−(4)Subtract equation 3 from equation 4: 8y+5z=7
(c) This time I would choose equation 1 and equation 2.
−3x+2y+z=−6−−−−−(1)x+3y+2z=5−−−−−(2)From equation 2: 3x+9y+6z=15−−−−−(5)Add equation 1 and equation 5: 11y+7z=9
(d)
{8y+5z=711y+7z=988y+55z=7788y+56z=72z=72−77=−588y+55(−5)=77y=4
(e) Because (y, z) = (4, -5),
x+3y+2z=5x+12−10=5x=3
Therefore (x, y, z) = (3, 4, -5).
:D