And this is to....?
Click here for a video on solving systems by elimination. Hope this helps!
Need the sketch.
Ok, so let's use substitution to do this.
x-4=4x-10
Subtract x from both sides.
-4=3x-10
Add 10 to both sides.
3x=6
divide by 3 on both sides.
x=2.
No. 2/14 simplified is 1/7.
1/7 < 3/7
Water is 2 hydrogen and one oxygen combined by covalent bonds. 2/3+2/4 = 8/12+6/12=14/12=1 1/6
Dissecting, spawn. Dissecting.
If x=3, then the problem turns into (9(3)-5)
27-5
22
They mean the outside of a circle.
Going to assume this equals 0.
-2g+7 -(g+11)
Distribute the negative 1.
-2g+7-g-11
Combine like terms.
-3g-4=0
Add 4 on both sides.
-3g=4
Divide by negative 3.
g=4
-3
g= -4
3
