SparklingWater2

Lets say Galvin has x books left to read for fiction books. (X + 13) + (3x/4 + 6) = all books bought

(x+13)=5(3x/4 + 6)/3

3x+39=15x/4+30

3x/4=9

x=12

12+13+9+6=$\boxed{40}$

We know that (a+b)(b-a) simplifies to b^2-a^2 so the least possible value is if b=1 and a=2:

1-4=$\boxed{-3}$

We can use the quadratic formula:

$\frac{-17\pm\sqrt{289-88}}{4}$ are the roots. $ab=\frac{-17+\sqrt{289-88}}{4}\cdot\frac{-17-\sqrt{289-88}}{4}=\frac{289-201}{16}=\frac{11}2$

$a+b=\frac{-17+\sqrt{289-88}}{4}+\frac{-17-\sqrt{289-88}}{4}=-\frac{17}2$

$ab+a+b=\frac{11-17}{2}=\boxed{-3}$

Because the discriminant must be 0, k will have a positive and a negative that have the same absolute value(sorry for the excessive use of the word value XD), which means that the average of the two values will be $\boxed0$

Remember, they are using the same dice, so 2,3 is the same as 3,2

It seems correct to me

5 x 7 x 6 = $\boxed{210}$

If the line of symmetry is the diagonal, then the minimum amount of squares needed to be colored in is 4.

You don't have to ask for one person specifically. Other people can help too, unless this is a problem you specifically want him/her to answer because of something.

Lets say Anson spends x dollars each day:

4x = 1/4 of initial amount

16x = initial amount

4x + 6x = 16x - 72

6x = 72

x = 12

so 16x = 16 x 12 = $\boxed{192}$