tertre

36-20=16 students-take part in only the mathematics club.

27-20=7 students only take part in the physics club.

16+7+20=43 students

Thus, 50-43=7 students take neither mathematics or physics clubs.

n can be either 12 or 14, thus 12+14=26-sum of the values for n.

50-6=44 students participate in at least some activity...

Let y be the number of students who participate in both MATHCOUNTS and the science club.

(28-y)+(21-y)+y=44

49-y=44

y=5.

Five(5) students participate in both MATHCOUNTS and science club.

Let c be the number of cheese pizzas and p be the number of pepperoni pizzas.

By systems of equations, we have:

6c+7p=153.50

2c+2p=47.00

...........................................

c+p=23.50,   6c+6p=141.00

Thus, the cost of one pepperoni pizza is $12.50.

I can't think straight..

the answer should be 7*7*7*7*4=9604 numbers.

It's always better to draw the diagram first.

The answer is sixty-degrees.

The place values can be anything, anything, odd

7*7*4=196 odd-five digit numbers.

the common difference is five.

-33+5(y)=57

5y=90

y=18

1+18=19 terms in the sequence.

Note that it states  "thousand" not "thousandths"

I'M Sso sorryyyyy

it should be 20*5=100

sorry again