1. What is the exact value of sin 60dg? Answer as a fraction in simplest form.

1. $\sin 60^{\circ} = \dfrac{\sqrt 3}{2}$

2. Area of the triangle = $\dfrac{1}{2}\cdot 12\cdot 8 \cdot \sin65^{\circ}\\ =48 \sin 65^{\circ}\\\approx 43.5\text{cm}^2$