5x^2-3x+1=0

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5x^2-3x+1=0

Guest Jun 26, 2014

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Best Answer

$\underbrace{5}_{a=5}x^2\underbrace{-3}_{b=-3}x\underbrace{+1}_{c=1}=0 \quad ?$

$discriminant = b^2-4ac =(-3)^2-4*5*1=9-20=-11$

$\textcolor[rgb]{1,0,0}{discriminant < 0\qquad \mbox{no real solution}}$

heureka Jun 26, 2014

heureka · Answer 1 · 2014-06-26T04:20:52

$\underbrace{5}_{a=5}x^2\underbrace{-3}_{b=-3}x\underbrace{+1}_{c=1}=0 \quad ?$

$discriminant = b^2-4ac =(-3)^2-4*5*1=9-20=-11$

$\textcolor[rgb]{1,0,0}{discriminant < 0\qquad \mbox{no real solution}}$

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