a picture frame is 18cm by 14cm. If 165 cm^2 of a picture shows, find the width of the frame.
OK...assuming the frame width is uniform..let's call this "x"
So....the total area that the frame encloses is 18 * 14.
So......the area occupied by the picture itself can be expressed as
(18-2x)(14-2x) = 165
252 - 64x + 4x^2 = 165 subtract 165 from both sides
4x^2 - 64x + 87 = 0 factor this.....
(2x - 29) (2x -3) = 0 set each factor to 0
2x - 29 = 0 x =14.5 cm reject this.........the frame width would cover the picture !!!
2x - 3 = 0 x = 1.5 cm......that seems reasonable
Also (18 - 2(1.5)) * ( 14 - 2(1.5)) = (18 -3) * ( 14 -3) = (15) * (11) = 165 cm
This seems to "sync-up" with the info given
So the frame is 1.5 cm wide.
OK...assuming the frame width is uniform..let's call this "x"
So....the total area that the frame encloses is 18 * 14.
So......the area occupied by the picture itself can be expressed as
(18-2x)(14-2x) = 165
252 - 64x + 4x^2 = 165 subtract 165 from both sides
4x^2 - 64x + 87 = 0 factor this.....
(2x - 29) (2x -3) = 0 set each factor to 0
2x - 29 = 0 x =14.5 cm reject this.........the frame width would cover the picture !!!
2x - 3 = 0 x = 1.5 cm......that seems reasonable
Also (18 - 2(1.5)) * ( 14 - 2(1.5)) = (18 -3) * ( 14 -3) = (15) * (11) = 165 cm
This seems to "sync-up" with the info given
So the frame is 1.5 cm wide.