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A circle has the equaton (x-2)^2+(y+3)^2=4 and a line has the equation 5y-4x+20=0. 

 

a) What is the distance from the center of the circel to the line. 

 

b) What is the greatest distance from a point on the circle to the line?

 

Thanks!

 Jun 15, 2020
 #1
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a)
Center = (2, -3).

 

Using the point-line distance formula: 

Distance between (x0,y0) and the line ax+by+c=0=|ax0+by0+c|a2+b2

 

Plugging in (x0,y0,a,b,c)=(2,3,4,5,20) gives the answer.

 

b)

In this case, you plot a straight line perpendicular to 5y - 4x + 20 = 0, which passes through the center of the circle. This straight line intersects the circle twice. For each intersection, calculate the point-line distance between the intersection and the straight line 5y - 4x + 20 = 0. The smaller one is the minimum distance, and the larger one is the required answer.

 Jun 15, 2020

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