Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
3
1
avatar+657 

Assume that f(3) = 4. Name a point that must be on the graph of y= (5 + f(2x/3))/11$.

 Jan 29, 2025
 #1
avatar+130383 
+1

We need to  make f(2x/3)  = f(3)

So...   2x / 3  = 3 →  2x = 9 →  x = 9/2  = 4.5

 

So....remembering that f(3)  =  4 we have

 

5 + f( 2(4.5) / 3) / 11  =   5 + f(9/3) / 11  =   5 + f(3)/11  =  5 + 4 / 11  =  59 / 11

 

The point is  (4.5 , 59/11)

 

cool cool cool

 Jan 29, 2025

2 Online Users