Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
13
1
avatar+448 

The parabola y = ax^2 + bx + c is graphed below. Find a + b + c. (The grid lines are one unit apart.)
The parabola passes through (-2,8), (0,0), and (2,8).

 Jan 14, 2025
 #1
avatar+130466 
+1

Since it passes through (0,0) then c  =  0

 

So

 

a(-2)^2 + b(-2)   =  8

a(2)^2 + b(2)  =  8           add these

 

8a   =  16

 

a =  2

 

And to find b

 

2 (2)^2 + b(2)  = 8

 

8 + 2b = 8

 

2b = 0

 

b  = 0

 

a + b + c  =

 

2 + 0 + 0  =  

 

2

 

cool cool cool

 Jan 15, 2025

0 Online Users