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anonymous

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664

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nd=In(de^s)+In(nu/s)

Guest Feb 2, 2017

1⁺⁰ Answers

+9675

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Hi anonymous.

$nd = \ln(de^s)+\ln\left(\dfrac{nu}{s}\right)\\ nd = \ln d + s\ln e +\ln n + \ln u - \ln s$

What do you want to know about?

MaxWong Feb 2, 2017

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