Loading [MathJax]/jax/element/mml/optable/BasicLatin.js
 
+0  
 
-2
626
1
avatar+318 

Let f(x)= x^3+3x^2-24x+23

 

** I ALREADY GOT THE FIRST PART. IT SAYS USE DEFINITION OF A DERIVATIVE to find f'(x)= 3x^2+6x-24

 

please help with these::::

b) use the definition of a derivative to find f '' (x)= _____??

c) on what interval is f increasing (include the endpoints in the interval)=___???

d) interval f decreasing =_____???

e) what interval is f concave downward???____?

f) interval is f convave upard???____

 Jun 11, 2020
 #1
avatar+9675 
+1

You can use the definition of derivative on f(x) to find f(x) because f(x)=lim.

 

If f is increasing on an interval , then for all real numbers .

 

If f is decreasing on an interval , then for all real numbers .

 

If f is concave downward on an interval , then for all real numbers .

 

If f is concave upward on an interval , then for all real numbers .

 

These are the definitions. I believe you can finish the rest with these.

 Jun 11, 2020

1 Online Users

avatar