+20 1. Trapezoid HGFE is inscribed in a circle, with EF || GH. If arc GH is 70 degrees, arc EH is x^2 - 2x degrees, and arc FG is 56 - 3x degrees, where x > 0 find arc EPF, in degrees.
(btw i will post the next qustions after I see the answer. May the best player win!!)
+9675 arc EH = arc FG
x2−2x=56−3xx2+x−56=0(x+8)(x−7)=0x=−8(rej.) or x=7
Both arcs are 35 degrees.
arc EPF = 360∘−70∘−2⋅35∘=220∘
+20 YAY A RIGHT ANSWER
2. In cylic quadrilateral PQRS,
∠P2=∠Q3=∠R4.
Find the largest angle of quadrilateral PQRS in degrees.
GO GO Go GO GO
