A line has slope 2. Find the area of the triangle formed by this line and the coordinate axes, if the distance between the origin and the line is 8
Deleted
Find the area of the triangle.
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Touch Point P:xP=8⋅cos(atan−12)=7.155yP=8⋅sin(atan−12)=−3.578f(x)=2⋅(x−xP)+yPf(x)=2x−2⋅7.155−3.578f(x)=2x−17.888=0Px (8.944,0)Py(0,−17.888)
The area of this triangle is
Axy=12⋅8.944⋅(−17.888)
Axy=−79.995
!