Does 1+1=0 ?

You can only use the $ in this context for text.  Plus it only usually lets you do it once per line.

It is good to know more than one method to do things because sometimes, for no apparent reason, a command just won't work!

$$\\\:I'm\:possitive\:it\:equals\:Zero\\\You\:made\:LaTeX\:look\:like\:a\:walk\:in\:the\:park\\This\:my\:first\:time\:using\:it$$

Well......I think that you've made a mistake....because

$${\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{2}}$$

If you think that all that calculation are wrong, then find a miscalculation.

MathsGod1, you did a good job with that LaTex,

Here is another way you could have done it

$$\\$I'm positive it equals zero (it doesn't by the way)$\\ $made Latex look like a walk in the park$\\ $this is my first time using it$\\\\ OR\\\\ \\\text{I'm positive it equals zero (it doesn't by the way)}\\ \text{made Latex look like a walk in the park}\\ \text{ this is my first time using it}\\\\ OR\\\\ \\\mbox{I'm positive it equals zero (it doesn't by the way)}\\ \mbox{made Latex look like a walk in the park}\\ \mbox{ this is my first time using it}\\\\$$

HERE IS THE CODE :)

\\$I'm positive it equals zero (it doesn't by the way)$\\

$made Latex look like a walk in the park$\\

$this is my first time using it$\\\\

OR\\\\

\text{I'm positive it equals zero (it doesn't by the way)}\\

\text{made Latex look like a walk in the park}\\

\text{ this is my first time using it}\\\\

OR\\\\

\mbox{I'm positive it equals zero (it doesn't by the way)}\\

\mbox{made Latex look like a walk in the park}\\

\mbox{ this is my first time using it}\\\\

(you will have to take the extra line breaks out, I put them in so it is easier to read)

There are a lot of different ways of doing the same things in LaTex, I really do not know why.  :/

mbox stands for message box.

$$\\\mathbf{i}=\sqrt{-1}\\ \sqrt{ab}=\sqrt{a}\times \sqrt{b}\\ \textup{So:}\\ 1+1=1+\sqrt{1}\\ =1+\sqrt{(-1)\times(-1)}\qquad or \qquad 1+\sqrt{1}\times \sqrt{1}\\ =1+\sqrt{-1}\times \sqrt{-1}\qquad or \qquad 1+\sqrt{1}\times \sqrt{1} \\ =1+\mathbf{i}\times \mathbf{i}\qquad or \qquad 1+1\\ =1\times \mathbf{i}^2\qquad or \qquad 1+ 1\\ =1+(-1) \;\;or\;\; 2\\ =1-1 \;\;or\;\; 2\\ =0 \;\;or\;\; 2$$

0 can be discounted as an incorrect answer :)

Wow thanks Melody for your imput.

There are so many ways to leave spaces but i prefer your method with : \: , \; , \quad , \qquad.

I'll treasure that and learn from it :)

EDIT: I might go with $ $ it looks a lot easier than after every word doing a backslash.