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what is the value of n such that, 81^n=9*27*27*9?

 Jan 8, 2023
 #1
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 81^n=9*27*27*9?

 

n ==Log[9*27*27*9) / log(81)

 

n==2.5

 Jan 8, 2023
 #2
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Alternatively:

 

81n=92n

 

927279=939399=95

 

Hence 92n=95  so 2n=5  or n=5/2

 Jan 8, 2023

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