help asap

I assumed that the 120-degree angle is between the two equal sides.

Use the law of Cosines to find the 3rd side of the triangle:

Obtuse isosceles triangle.

Sides: a = 12   b = 12   c = 20.785

Area: T = 62.354
Perimeter: p = 44.785
Semiperimeter: s = 22.392

Angle ∠ A = α = 30° = 0.524 rad
Angle ∠ B = β = 30° = 0.524 rad
Angle ∠ C = γ = 120° = 2.094 rad

Height: ha = 10.392
Height: hb = 10.392
Height: hc = 6

We can use the formula $A = \dfrac12 ab \sin C$ directly.

$A = \dfrac12 \cdot 12^2 \cdot \sin 120^\circ = 72 \cdot \dfrac{\sqrt 3}2 = 36\sqrt 3$