Given DE||AB,AC=15,DC=10,EC=8. find BE
do you have a picture?
Im assuming its something like this: (I cant be sure I dont want to solve the wrong question.)
yes..its something like that only that
You should upload the actual picture.
only that what.
By intercept theorem,
ACDA=BCBE1515−10=8+BEBE15BE=40+5BE10BE=40BE=4