If a haystack in the shape of a right circular cone has a base radius of 5 meters and contains 12 tons of hay, what will be the number of tons of hay in a similar conical haystack whose base diameter is 15 meters? Two right cones are similar if their heights and their base radii are in proportion. Express your answer as a decimal to the nearest tenth.
+9488 The radius of the first cone is 5 meters,
so the diameter of the first cone is 10 meters.
The diameter of the second cone is 15 meters.
volume of second conevolume of first cone=(diameter of second conediameter of first cone)3 volume of second conevolume of first cone=(1510)3 volume of second conevolume of first cone=(32)3 volume of second conevolume of first cone=(32)(32)(32) volume of second conevolume of first cone=278 volume of second cone=278⋅volume of first cone
Assuming that both haystacks have the same density, and each piece of hay weighs the same....
weight of second cone=278⋅weight of first cone weight of second cone=278⋅12 tons weight of second cone=40.5 tons
