Help me

volume of one and one half ten-ounce cans

= 3/2 x 10

= 15 ounce.

Let x ounce be the volume of the pitcher at least.

$\dfrac{1}{4\dfrac{1}{3}}=\dfrac{15}{x}\\ x = \dfrac{13}{3}\times 15 = 65$

The volume of the pitcher must be at least 65 ounce.

[4 + 1/3] cans water   =  [4 + 1/3]*10 ounces of water

1 + 1/2  cans of concentrate = 15 ounces of concentrate

So

[ 4 + 1/3]*10 ounces of water / 10 ounces of concentrate  =  ????/ 15 onces of concentrate

Multiply both sides by 15

(15/10)  * [ 4 + 1/3]*10 ounces of water  =  65 ounces of water

But....we need to combine the amount of water and the amount of concentrate....

So.........65 ounces of water + 15 ounces of concentrate = 80 ounce pitcher