help

nope

2x²  =  4x + 9

                               Subtract  4x  from both sides of the equation.

2x² - 4x  =  9

                               Subtract  9  from both sides of the equation.

2x² - 4x - 9  =  0

                               By the quadratic formula,

x  =  ${-(-4) \pm \sqrt{(-4)^2-4(2)(-9)} \over 2(2)}\ =\ \frac{4\pm\sqrt{16+72}}{4}\ =\ \frac{4\pm\sqrt{88}}{4}\ =\ \frac{4\pm2\sqrt{22}}{4}\ =\ \frac{2\pm\sqrt{22}}{2}$

We're given that  x  is positive so....

x  =  $\frac{2+\sqrt{22}}{2}$

Now it is in simplified form as   $\frac{a+\sqrt{b}}{c}$   where  a,  b,  and  c  are positive integers.

a + b + c   =   2 + 22 + 2   =   26

$\begin{array}{rcll} 2x^2 &=& 4x + 9\\ 2x^2 - 4x - 9 &=& 0\\ x &=&\dfrac{4\pm\sqrt{16+4\cdot2\cdot9}}{4}\\ x &=& \dfrac{4\pm2\sqrt{22}}4\\ x &=& \dfrac{2\pm\sqrt{22}}2\\ a + b + c &=&2 + 22 + 2 \\ a + b + c &=& 26 \end{array}$