Balamurugan: 10^X=2912.35/10power X = 2912.35 then X= ?
X = ?
Looks to me as if it's the same question twice (written slightly differently); namely, given 10
X=2912.35 what is X?
The way to do this is to take logs (to the base 10) of both sides. log
1010
X is just X, so X = log
102912.35
On the calculator here, just using the word log means log to the base 10 so
X = log(2912.35)
+118703 
+33658 
