HELP

Compute f '(a) algebraically for the given value of a. f(x) = 6x2 + x; a = 1

$f(x) = 6x^2 + x\\ f'(x) =12x + 1\\ f'(a) =12a + 1\\ f'(1) =12*1 + 1\\ f'(1) =13\\$

To do this question, differentiate f(x) first.

$f(x) = 6x^2+x$

$\frac{d}{dx}f(x) = f'(x) = 12x + 1$

$f'(a) = 12a +1$

When a = 1,

$f'(1) = 12(1) + 1 = 13$