Move the terms around so we have a quadratic equation.
2x2−10x+35=x2+10x2−10x−25=0
Now we can simply solve for x using the quadratic formula. Let a=1, b=-10, and c=-25.
x=−b±√b2−4ac2ax=10±√(−10)2−4(1)(−25)2(1)x=10±√2002x=10±10√22x=5±5√2
So x is 5+√2 and 5−√2.