Find all ordered pairs of real nubmers (a,b) for which 3*sqrt(x - 2y) + 3/sqrt(x - 2y) = 10 and x = ay + b.
3√x−2y+3√x−2y=103(√x−2y)2−10√x−2y+3=0,x≠2y√x−2y=13 or √x−2y=3x−2y=19 or x−2y=9(a−2)y+b=19 or (a−2)y+b=9Assuming the above equations are true for all values of y,(a,b)=(2,19) or (2,9)
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