How do I solve for n in:

How do I solve for n in: 0.25 = 0.5^n

$$\begin{array}{rcl} 0.25 & = & 0.5^n\\\\ \dfrac{1}{4} &=& \left(\dfrac{1}{2} \right)^n\\\\ \dfrac{1}{2^2} &=& \dfrac{1}{2^n} \\\\ 2^2 &=& 2^n \\ 2&=& n \end{array}$$

$$\boxed{n= 2}$$