if 3y + 5 = -10 what would y be?

3y + 5 = -10

3y = -10 - 5 ---  Shift 5 to right side of equal which changes it from a positive 5 to a negative 5
3y = -15 ---  -10 - 5 = -15

 y = -5 ---  Since both sides are divisible by 3, we divide them by 3 to simplify the answer. 3y / 3 = y & -15 / 3 = -5

$3y+5=-10$

$3y+5-5=-10-5$

$3y=-15$

$\frac{3y}{3}=\frac{-15}{3 }$

$y=-5$