If f(θ) = 2 sinθ - sin θ/2, find f(π/3)

 f(θ) = 2 sinθ - sin θ/2     $$f(\dfrac{\pi}{3}) \quad ? \qquad \Theta = \dfrac{\pi}{3}$$

$$\sin{ \Theta } = \sin{ \dfrac{\pi}{3} } = \dfrac {1}{2}\sqrt{3}$$

$$\sin{ \dfrac{\Theta}{2} } = \sin{ \left( \dfrac{\pi}{3}*\dfrac{1}{2} \right) } = \sin{ \dfrac{\pi}{6} } = \dfrac {1}{2}$$

$$f(\dfrac{\pi}{3}) = 2*\dfrac {1}{2}\sqrt{3} -\dfrac {1}{2}$$

$$f(\dfrac{\pi}{3}) = \sqrt{3}-\dfrac {1}{2} =1.2320508075688773$$