Inequality

$8+x<4-3x-7<5x-4+11$

 

$8+x<4-3x-7\quad \mathrm{and}\quad \:4-3x-7<5x-4+11$

 

$x<-\frac{11}{4}\quad \mathrm{and}\quad \:x>-\frac{5}{4}$

 

Since they are overlapping intervals:

 

No Solution

 

-Vinculum