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R\textupisthesetofrealnumbers.Foranynumberx\textupinR:x20(x2)1/201/2x2×1/20x10x0



Are all these calculations correct ? Or is there some form of miscalculation ?

 May 2, 2015

Best Answer 

 #3
avatar+118703 
+5

Thanks EinstienJr,

did you already know the problem with the question?

If you did you really should say so up front because otherwise, one day you will  ask a 'real' question and I will think,

I won't answer that because I am buy and I expect that he/she already knows the answer. :)

 May 3, 2015
 #1
avatar+118703 
+5

There is a bit of a problem here Einstein,

I have been struggling with exactly the same problem on complex number questions lately.

 

(x2)1/2>0true

 

consider

x2=36x2=±6$Iputthesquarerootinsobothanswersarevalid$

 

so

(x2)1/20±x0$either$x0orx0$either$x0orx0$Hencexisanyrealnumber$

 May 2, 2015
 #2
avatar+870 
0

Exactly. Here's your cookie, Melody:

Cookie

 May 2, 2015
 #3
avatar+118703 
+5
Best Answer

Thanks EinstienJr,

did you already know the problem with the question?

If you did you really should say so up front because otherwise, one day you will  ask a 'real' question and I will think,

I won't answer that because I am buy and I expect that he/she already knows the answer. :)

Melody May 3, 2015

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