R\textupisthesetofrealnumbers.Foranynumberx\textupinR:x2≥0(x2)1/2≥01/2x2×1/2≥0x1≥0x≥0
Thanks EinstienJr,
did you already know the problem with the question?
If you did you really should say so up front because otherwise, one day you will ask a 'real' question and I will think,
I won't answer that because I am buy and I expect that he/she already knows the answer. :)
There is a bit of a problem here Einstein,
I have been struggling with exactly the same problem on complex number questions lately.
(x2)1/2>0true
consider
x2=36√x2=±6$Iputthesquarerootinsobothanswersarevalid$
so
(x2)1/2≥0±x≥0$either$x≥0or−x≥0$either$x≥0orx≤0$Hencexisanyrealnumber$
Thanks EinstienJr,
did you already know the problem with the question?
If you did you really should say so up front because otherwise, one day you will ask a 'real' question and I will think,
I won't answer that because I am buy and I expect that he/she already knows the answer. :)